5(i+2)=8(i-1)*

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Solution for 5(i+2)=8(i-1)* equation: 



5(i+2)=8(i-1)*

We move all terms to the left:

5(i+2)-(8(i-1)*)=0

We multiply parentheses

5i-(8(i-1)*)+10=0



We calculate terms in parentheses: -(8(i-1)*), so:

8(i-1)*

We multiply parentheses

8i-8

Back to the equation:

-(8i-8)



We get rid of parentheses

5i-8i+8+10=0

We add all the numbers together, and all the variables

-3i+18=0

We move all terms containing i to the left, all other terms to the right

-3i=-18

i=-18/-3

i=+6

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