5(i+2)=8(i-2)

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Solution for 5(i+2)=8(i-2) equation: 



5(i+2)=8(i-2)

We move all terms to the left:

5(i+2)-(8(i-2))=0

We multiply parentheses

5i-(8(i-2))+10=0



We calculate terms in parentheses: -(8(i-2)), so:

8(i-2)

We multiply parentheses

8i-16

Back to the equation:

-(8i-16)



We get rid of parentheses

5i-8i+16+10=0

We add all the numbers together, and all the variables

-3i+26=0

We move all terms containing i to the left, all other terms to the right

-3i=-26

i=-26/-3

i=8+2/3

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