5(i-1)=2i+4(i-1)

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Solution for 5(i-1)=2i+4(i-1) equation: 



5(i-1)=2i+4(i-1)

We move all terms to the left:

5(i-1)-(2i+4(i-1))=0

We multiply parentheses

5i-(2i+4(i-1))-5=0



We calculate terms in parentheses: -(2i+4(i-1)), so:

2i+4(i-1)

We multiply parentheses

2i+4i-4

We add all the numbers together, and all the variables

6i-4

Back to the equation:

-(6i-4)



We get rid of parentheses

5i-6i+4-5=0

We add all the numbers together, and all the variables

-1i-1=0

We move all terms containing i to the left, all other terms to the right

-i=1

i=1/-1

i=-1

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