5(i-4)+6=8(i+7)-2(3i+5)

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Solution for 5(i-4)+6=8(i+7)-2(3i+5) equation: 



5(i-4)+6=8(i+7)-2(3i+5)

We move all terms to the left:

5(i-4)+6-(8(i+7)-2(3i+5))=0

We multiply parentheses

5i-(8(i+7)-2(3i+5))-20+6=0



We calculate terms in parentheses: -(8(i+7)-2(3i+5)), so:

8(i+7)-2(3i+5)

We multiply parentheses

8i-6i+56-10

We add all the numbers together, and all the variables

2i+46

Back to the equation:

-(2i+46)



We add all the numbers together, and all the variables

5i-(2i+46)-14=0

We get rid of parentheses

5i-2i-46-14=0

We add all the numbers together, and all the variables

3i-60=0

We move all terms containing i to the left, all other terms to the right

3i=60

i=60/3

i=20

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