5(j+3)=2(j-6)

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Solution for 5(j+3)=2(j-6) equation:


Simplifying
5(j + 3) = 2(j + -6)

Reorder the terms:
5(3 + j) = 2(j + -6)
(3 * 5 + j * 5) = 2(j + -6)
(15 + 5j) = 2(j + -6)

Reorder the terms:
15 + 5j = 2(-6 + j)
15 + 5j = (-6 * 2 + j * 2)
15 + 5j = (-12 + 2j)

Solving
15 + 5j = -12 + 2j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-2j' to each side of the equation.
15 + 5j + -2j = -12 + 2j + -2j

Combine like terms: 5j + -2j = 3j
15 + 3j = -12 + 2j + -2j

Combine like terms: 2j + -2j = 0
15 + 3j = -12 + 0
15 + 3j = -12

Add '-15' to each side of the equation.
15 + -15 + 3j = -12 + -15

Combine like terms: 15 + -15 = 0
0 + 3j = -12 + -15
3j = -12 + -15

Combine like terms: -12 + -15 = -27
3j = -27

Divide each side by '3'.
j = -9

Simplifying
j = -9

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