5(j-2)+2j=5

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Solution for 5(j-2)+2j=5 equation: 



5(j-2)+2j=5

We move all terms to the left:

5(j-2)+2j-(5)=0

We add all the numbers together, and all the variables

2j+5(j-2)-5=0

We multiply parentheses

2j+5j-10-5=0

We add all the numbers together, and all the variables

7j-15=0

We move all terms containing j to the left, all other terms to the right

7j=15

j=15/7

j=2+1/7

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