5(j-4)=3(j+2)

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Solution for 5(j-4)=3(j+2) equation: 



5(j-4)=3(j+2)

We move all terms to the left:

5(j-4)-(3(j+2))=0

We multiply parentheses

5j-(3(j+2))-20=0



We calculate terms in parentheses: -(3(j+2)), so:

3(j+2)

We multiply parentheses

3j+6

Back to the equation:

-(3j+6)



We get rid of parentheses

5j-3j-6-20=0

We add all the numbers together, and all the variables

2j-26=0

We move all terms containing j to the left, all other terms to the right

2j=26

j=26/2

j=13

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