5(j-6)+6(j-22)=3

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Solution for 5(j-6)+6(j-22)=3 equation: 



5(j-6)+6(j-22)=3

We move all terms to the left:

5(j-6)+6(j-22)-(3)=0

We multiply parentheses

5j+6j-30-132-3=0

We add all the numbers together, and all the variables

11j-165=0

We move all terms containing j to the left, all other terms to the right

11j=165

j=165/11

j=15

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