5(k+2)-3=2(k+5)

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Solution for 5(k+2)-3=2(k+5) equation: 



5(k+2)-3=2(k+5)

We move all terms to the left:

5(k+2)-3-(2(k+5))=0

We multiply parentheses

5k-(2(k+5))+10-3=0



We calculate terms in parentheses: -(2(k+5)), so:

2(k+5)

We multiply parentheses

2k+10

Back to the equation:

-(2k+10)



We add all the numbers together, and all the variables

5k-(2k+10)+7=0

We get rid of parentheses

5k-2k-10+7=0

We add all the numbers together, and all the variables

3k-3=0

We move all terms containing k to the left, all other terms to the right

3k=3

k=3/3

k=1

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