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5(k+2)-7/9=13-(4-k)/9
We move all terms to the left:
5(k+2)-7/9-(13-(4-k)/9)=0
We add all the numbers together, and all the variables
5(k+2)-(13-(-1k+4)/9)-7/9=0
We multiply parentheses
5k-(13-(-1k+4)/9)+10-7/9=0
We calculate fractions
5k+10=0
We move all terms containing k to the left, all other terms to the right
5k=-10
k=-10/5
k=-2
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