5(k+2)-7/9=13-(4-k)/9

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Solution for 5(k+2)-7/9=13-(4-k)/9 equation: 



5(k+2)-7/9=13-(4-k)/9

We move all terms to the left:

5(k+2)-7/9-(13-(4-k)/9)=0

We add all the numbers together, and all the variables

5(k+2)-(13-(-1k+4)/9)-7/9=0

We multiply parentheses

5k-(13-(-1k+4)/9)+10-7/9=0

We calculate fractions


5k+10=0

We move all terms containing k to the left, all other terms to the right

5k=-10

k=-10/5

k=-2

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