5(k+2)-k-3=-6(k+3)+5

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Solution for 5(k+2)-k-3=-6(k+3)+5 equation: 



5(k+2)-k-3=-6(k+3)+5

We move all terms to the left:

5(k+2)-k-3-(-6(k+3)+5)=0

We add all the numbers together, and all the variables

-1k+5(k+2)-(-6(k+3)+5)-3=0

We multiply parentheses

-1k+5k-(-6(k+3)+5)+10-3=0



We calculate terms in parentheses: -(-6(k+3)+5), so:

-6(k+3)+5

We multiply parentheses

-6k-18+5

We add all the numbers together, and all the variables

-6k-13

Back to the equation:

-(-6k-13)



We add all the numbers together, and all the variables

4k-(-6k-13)+7=0

We get rid of parentheses

4k+6k+13+7=0

We add all the numbers together, and all the variables

10k+20=0

We move all terms containing k to the left, all other terms to the right

10k=-20

k=-20/10

k=-2

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