5(k+2)=2(k-4)

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Solution for 5(k+2)=2(k-4) equation: 



5(k+2)=2(k-4)

We move all terms to the left:

5(k+2)-(2(k-4))=0

We multiply parentheses

5k-(2(k-4))+10=0



We calculate terms in parentheses: -(2(k-4)), so:

2(k-4)

We multiply parentheses

2k-8

Back to the equation:

-(2k-8)



We get rid of parentheses

5k-2k+8+10=0

We add all the numbers together, and all the variables

3k+18=0

We move all terms containing k to the left, all other terms to the right

3k=-18

k=-18/3

k=-6

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