5(k+2)=4(k+1)

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Solution for 5(k+2)=4(k+1) equation: 



5(k+2)=4(k+1)

We move all terms to the left:

5(k+2)-(4(k+1))=0

We multiply parentheses

5k-(4(k+1))+10=0



We calculate terms in parentheses: -(4(k+1)), so:

4(k+1)

We multiply parentheses

4k+4

Back to the equation:

-(4k+4)



We get rid of parentheses

5k-4k-4+10=0

We add all the numbers together, and all the variables

k+6=0

We move all terms containing k to the left, all other terms to the right

k=-6

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