5(k-2)-6=4k-(3k-2)

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Solution for 5(k-2)-6=4k-(3k-2) equation: 



5(k-2)-6=4k-(3k-2)

We move all terms to the left:

5(k-2)-6-(4k-(3k-2))=0

We multiply parentheses

5k-(4k-(3k-2))-10-6=0



We calculate terms in parentheses: -(4k-(3k-2)), so:

4k-(3k-2)

We get rid of parentheses

4k-3k+2

We add all the numbers together, and all the variables

k+2

Back to the equation:

-(k+2)



We add all the numbers together, and all the variables

5k-(k+2)-16=0

We get rid of parentheses

5k-k-2-16=0

We add all the numbers together, and all the variables

4k-18=0

We move all terms containing k to the left, all other terms to the right

4k=18

k=18/4

k=4+1/2

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