5(k-2)-6=5k-(4k-1)

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Solution for 5(k-2)-6=5k-(4k-1) equation: 



5(k-2)-6=5k-(4k-1)

We move all terms to the left:

5(k-2)-6-(5k-(4k-1))=0

We multiply parentheses

5k-(5k-(4k-1))-10-6=0



We calculate terms in parentheses: -(5k-(4k-1)), so:

5k-(4k-1)

We get rid of parentheses

5k-4k+1

We add all the numbers together, and all the variables

k+1

Back to the equation:

-(k+1)



We add all the numbers together, and all the variables

5k-(k+1)-16=0

We get rid of parentheses

5k-k-1-16=0

We add all the numbers together, and all the variables

4k-17=0

We move all terms containing k to the left, all other terms to the right

4k=17

k=17/4

k=4+1/4

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