5(k-2)-7=3k-(2k-1)

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Solution for 5(k-2)-7=3k-(2k-1) equation: 



5(k-2)-7=3k-(2k-1)

We move all terms to the left:

5(k-2)-7-(3k-(2k-1))=0

We multiply parentheses

5k-(3k-(2k-1))-10-7=0



We calculate terms in parentheses: -(3k-(2k-1)), so:

3k-(2k-1)

We get rid of parentheses

3k-2k+1

We add all the numbers together, and all the variables

k+1

Back to the equation:

-(k+1)



We add all the numbers together, and all the variables

5k-(k+1)-17=0

We get rid of parentheses

5k-k-1-17=0

We add all the numbers together, and all the variables

4k-18=0

We move all terms containing k to the left, all other terms to the right

4k=18

k=18/4

k=4+1/2

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