5(k-4)-1=7(k-3)-2k

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Solution for 5(k-4)-1=7(k-3)-2k equation:


Simplifying
5(k + -4) + -1 = 7(k + -3) + -2k

Reorder the terms:
5(-4 + k) + -1 = 7(k + -3) + -2k
(-4 * 5 + k * 5) + -1 = 7(k + -3) + -2k
(-20 + 5k) + -1 = 7(k + -3) + -2k

Reorder the terms:
-20 + -1 + 5k = 7(k + -3) + -2k

Combine like terms: -20 + -1 = -21
-21 + 5k = 7(k + -3) + -2k

Reorder the terms:
-21 + 5k = 7(-3 + k) + -2k
-21 + 5k = (-3 * 7 + k * 7) + -2k
-21 + 5k = (-21 + 7k) + -2k

Combine like terms: 7k + -2k = 5k
-21 + 5k = -21 + 5k

Add '21' to each side of the equation.
-21 + 21 + 5k = -21 + 21 + 5k

Combine like terms: -21 + 21 = 0
0 + 5k = -21 + 21 + 5k
5k = -21 + 21 + 5k

Combine like terms: -21 + 21 = 0
5k = 0 + 5k
5k = 5k

Add '-5k' to each side of the equation.
5k + -5k = 5k + -5k

Combine like terms: 5k + -5k = 0
0 = 5k + -5k

Combine like terms: 5k + -5k = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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