5(k-4)=3(k+2)

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Solution for 5(k-4)=3(k+2) equation: 



5(k-4)=3(k+2)

We move all terms to the left:

5(k-4)-(3(k+2))=0

We multiply parentheses

5k-(3(k+2))-20=0



We calculate terms in parentheses: -(3(k+2)), so:

3(k+2)

We multiply parentheses

3k+6

Back to the equation:

-(3k+6)



We get rid of parentheses

5k-3k-6-20=0

We add all the numbers together, and all the variables

2k-26=0

We move all terms containing k to the left, all other terms to the right

2k=26

k=26/2

k=13

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