5(k-5)=3k-(2k-3)

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Solution for 5(k-5)=3k-(2k-3) equation: 



5(k-5)=3k-(2k-3)

We move all terms to the left:

5(k-5)-(3k-(2k-3))=0

We multiply parentheses

5k-(3k-(2k-3))-25=0



We calculate terms in parentheses: -(3k-(2k-3)), so:

3k-(2k-3)

We get rid of parentheses

3k-2k+3

We add all the numbers together, and all the variables

k+3

Back to the equation:

-(k+3)



We get rid of parentheses

5k-k-3-25=0

We add all the numbers together, and all the variables

4k-28=0

We move all terms containing k to the left, all other terms to the right

4k=28

k=28/4

k=7

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