5(k-8)+k=2k-(1-k)

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Solution for 5(k-8)+k=2k-(1-k) equation: 



5(k-8)+k=2k-(1-k)

We move all terms to the left:

5(k-8)+k-(2k-(1-k))=0

We add all the numbers together, and all the variables

5(k-8)+k-(2k-(-1k+1))=0

We add all the numbers together, and all the variables

k+5(k-8)-(2k-(-1k+1))=0

We multiply parentheses

k+5k-(2k-(-1k+1))-40=0



We calculate terms in parentheses: -(2k-(-1k+1)), so:

2k-(-1k+1)

We get rid of parentheses

2k+1k-1

We add all the numbers together, and all the variables

3k-1

Back to the equation:

-(3k-1)



We add all the numbers together, and all the variables

6k-(3k-1)-40=0

We get rid of parentheses

6k-3k+1-40=0

We add all the numbers together, and all the variables

3k-39=0

We move all terms containing k to the left, all other terms to the right

3k=39

k=39/3

k=13

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