5(ln(x)/ln(7))-(ln(49x)/ln(7))=-2

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Solution for 5(ln(x)/ln(7))-(ln(49x)/ln(7))=-2 equation: 


D( x )

x <= 0

49*x <= 0

ln(7) = 0

x <= 0

49*x <= 0

49*x <= 0

49*x+0 <= 0 // - 0

49*x <= 0 // : 49

x <= 0/49

x <= 0

ln(7) = 0

ln(7) = 0

t_1 = ln(7)

ln(7) = 0

t_1 = 0

x należy do R

x in (-oo:+oo)

x belongs to the empty set

5*(ln(x)/ln(7))-(ln(49*x)/ln(7)) = -2

x belongs to the empty set

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