5(m)+3(2m+1)=65

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Solution for 5(m)+3(2m+1)=65 equation: 



5(m)+3(2m+1)=65

We move all terms to the left:

5(m)+3(2m+1)-(65)=0

We multiply parentheses

5m+6m+3-65=0

We add all the numbers together, and all the variables

11m-62=0

We move all terms containing m to the left, all other terms to the right

11m=62

m=62/11

m=5+7/11

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