5(m+1)+6=3(4+m)+(2m-1)

Solution for 5(m+1)+6=3(4+m)+(2m-1) equation:

Simplifying
5(m + 1) + 6 = 3(4 + m) + (2m + -1)

Reorder the terms:
5(1 + m) + 6 = 3(4 + m) + (2m + -1)
(1 * 5 + m * 5) + 6 = 3(4 + m) + (2m + -1)
(5 + 5m) + 6 = 3(4 + m) + (2m + -1)

Reorder the terms:
5 + 6 + 5m = 3(4 + m) + (2m + -1)

Combine like terms: 5 + 6 = 11
11 + 5m = 3(4 + m) + (2m + -1)
11 + 5m = (4 * 3 + m * 3) + (2m + -1)
11 + 5m = (12 + 3m) + (2m + -1)

Reorder the terms:
11 + 5m = 12 + 3m + (-1 + 2m)

Remove parenthesis around (-1 + 2m)
11 + 5m = 12 + 3m + -1 + 2m

Reorder the terms:
11 + 5m = 12 + -1 + 3m + 2m

Combine like terms: 12 + -1 = 11
11 + 5m = 11 + 3m + 2m

Combine like terms: 3m + 2m = 5m
11 + 5m = 11 + 5m

Add '-11' to each side of the equation.
11 + -11 + 5m = 11 + -11 + 5m

Combine like terms: 11 + -11 = 0
0 + 5m = 11 + -11 + 5m
5m = 11 + -11 + 5m

Combine like terms: 11 + -11 = 0
5m = 0 + 5m
5m = 5m

Add '-5m' to each side of the equation.
5m + -5m = 5m + -5m

Combine like terms: 5m + -5m = 0
0 = 5m + -5m

Combine like terms: 5m + -5m = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.