5(m+1)-3=3(4+m)+(2m-1)

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Solution for 5(m+1)-3=3(4+m)+(2m-1) equation:


Simplifying
5(m + 1) + -3 = 3(4 + m) + (2m + -1)

Reorder the terms:
5(1 + m) + -3 = 3(4 + m) + (2m + -1)
(1 * 5 + m * 5) + -3 = 3(4 + m) + (2m + -1)
(5 + 5m) + -3 = 3(4 + m) + (2m + -1)

Reorder the terms:
5 + -3 + 5m = 3(4 + m) + (2m + -1)

Combine like terms: 5 + -3 = 2
2 + 5m = 3(4 + m) + (2m + -1)
2 + 5m = (4 * 3 + m * 3) + (2m + -1)
2 + 5m = (12 + 3m) + (2m + -1)

Reorder the terms:
2 + 5m = 12 + 3m + (-1 + 2m)

Remove parenthesis around (-1 + 2m)
2 + 5m = 12 + 3m + -1 + 2m

Reorder the terms:
2 + 5m = 12 + -1 + 3m + 2m

Combine like terms: 12 + -1 = 11
2 + 5m = 11 + 3m + 2m

Combine like terms: 3m + 2m = 5m
2 + 5m = 11 + 5m

Add '-5m' to each side of the equation.
2 + 5m + -5m = 11 + 5m + -5m

Combine like terms: 5m + -5m = 0
2 + 0 = 11 + 5m + -5m
2 = 11 + 5m + -5m

Combine like terms: 5m + -5m = 0
2 = 11 + 0
2 = 11

Solving
2 = 11

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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