5(m+2)-2(3-4m)=3(m+5)-4(4-m)

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Solution for 5(m+2)-2(3-4m)=3(m+5)-4(4-m) equation: 



5(m+2)-2(3-4m)=3(m+5)-4(4-m)

We move all terms to the left:

5(m+2)-2(3-4m)-(3(m+5)-4(4-m))=0

We add all the numbers together, and all the variables

5(m+2)-2(-4m+3)-(3(m+5)-4(-1m+4))=0

We multiply parentheses

5m+8m-(3(m+5)-4(-1m+4))+10-6=0



We calculate terms in parentheses: -(3(m+5)-4(-1m+4)), so:

3(m+5)-4(-1m+4)

We multiply parentheses

3m+4m+15-16

We add all the numbers together, and all the variables

7m-1

Back to the equation:

-(7m-1)



We add all the numbers together, and all the variables

13m-(7m-1)+4=0

We get rid of parentheses

13m-7m+1+4=0

We add all the numbers together, and all the variables

6m+5=0

We move all terms containing m to the left, all other terms to the right

6m=-5

m=-5/6

m=-5/6

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