5(m+3)+2m=27

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Solution for 5(m+3)+2m=27 equation:



5(m+3)+2m=27
We move all terms to the left:
5(m+3)+2m-(27)=0
We add all the numbers together, and all the variables
2m+5(m+3)-27=0
We multiply parentheses
2m+5m+15-27=0
We add all the numbers together, and all the variables
7m-12=0
We move all terms containing m to the left, all other terms to the right
7m=12
m=12/7
m=1+5/7

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