5(m+3)+7=3(m-10)

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Solution for 5(m+3)+7=3(m-10) equation: 



5(m+3)+7=3(m-10)

We move all terms to the left:

5(m+3)+7-(3(m-10))=0

We multiply parentheses

5m-(3(m-10))+15+7=0



We calculate terms in parentheses: -(3(m-10)), so:

3(m-10)

We multiply parentheses

3m-30

Back to the equation:

-(3m-30)



We add all the numbers together, and all the variables

5m-(3m-30)+22=0

We get rid of parentheses

5m-3m+30+22=0

We add all the numbers together, and all the variables

2m+52=0

We move all terms containing m to the left, all other terms to the right

2m=-52

m=-52/2

m=-26

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