5(m+3)-25=6(2-m)

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Solution for 5(m+3)-25=6(2-m) equation:



5(m+3)-25=6(2-m)
We move all terms to the left:
5(m+3)-25-(6(2-m))=0
We add all the numbers together, and all the variables
5(m+3)-(6(-1m+2))-25=0
We multiply parentheses
5m-(6(-1m+2))+15-25=0
We calculate terms in parentheses: -(6(-1m+2)), so:
6(-1m+2)
We multiply parentheses
-6m+12
Back to the equation:
-(-6m+12)
We add all the numbers together, and all the variables
5m-(-6m+12)-10=0
We get rid of parentheses
5m+6m-12-10=0
We add all the numbers together, and all the variables
11m-22=0
We move all terms containing m to the left, all other terms to the right
11m=22
m=22/11
m=2

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