5(m+4)+12=3(m-2)

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Solution for 5(m+4)+12=3(m-2) equation: 



5(m+4)+12=3(m-2)

We move all terms to the left:

5(m+4)+12-(3(m-2))=0

We multiply parentheses

5m-(3(m-2))+20+12=0



We calculate terms in parentheses: -(3(m-2)), so:

3(m-2)

We multiply parentheses

3m-6

Back to the equation:

-(3m-6)



We add all the numbers together, and all the variables

5m-(3m-6)+32=0

We get rid of parentheses

5m-3m+6+32=0

We add all the numbers together, and all the variables

2m+38=0

We move all terms containing m to the left, all other terms to the right

2m=-38

m=-38/2

m=-19

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