5(m+4)=3(2m+1)

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Solution for 5(m+4)=3(2m+1) equation: 



5(m+4)=3(2m+1)

We move all terms to the left:

5(m+4)-(3(2m+1))=0

We multiply parentheses

5m-(3(2m+1))+20=0



We calculate terms in parentheses: -(3(2m+1)), so:

3(2m+1)

We multiply parentheses

6m+3

Back to the equation:

-(6m+3)



We get rid of parentheses

5m-6m-3+20=0

We add all the numbers together, and all the variables

-1m+17=0

We move all terms containing m to the left, all other terms to the right

-m=-17

m=-17/-1

m=+17

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