5(m+4)=3(2m+1)

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Solution for 5(m+4)=3(2m+1) equation:



5(m+4)=3(2m+1)
We move all terms to the left:
5(m+4)-(3(2m+1))=0
We multiply parentheses
5m-(3(2m+1))+20=0
We calculate terms in parentheses: -(3(2m+1)), so:
3(2m+1)
We multiply parentheses
6m+3
Back to the equation:
-(6m+3)
We get rid of parentheses
5m-6m-3+20=0
We add all the numbers together, and all the variables
-1m+17=0
We move all terms containing m to the left, all other terms to the right
-m=-17
m=-17/-1
m=+17

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