5(m-2)+1=4(m+3)

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Solution for 5(m-2)+1=4(m+3) equation: 



5(m-2)+1=4(m+3)

We move all terms to the left:

5(m-2)+1-(4(m+3))=0

We multiply parentheses

5m-(4(m+3))-10+1=0



We calculate terms in parentheses: -(4(m+3)), so:

4(m+3)

We multiply parentheses

4m+12

Back to the equation:

-(4m+12)



We add all the numbers together, and all the variables

5m-(4m+12)-9=0

We get rid of parentheses

5m-4m-12-9=0

We add all the numbers together, and all the variables

m-21=0

We move all terms containing m to the left, all other terms to the right

m=21

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