5(m-3)+6m=20

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Solution for 5(m-3)+6m=20 equation: 



5(m-3)+6m=20

We move all terms to the left:

5(m-3)+6m-(20)=0

We add all the numbers together, and all the variables

6m+5(m-3)-20=0

We multiply parentheses

6m+5m-15-20=0

We add all the numbers together, and all the variables

11m-35=0

We move all terms containing m to the left, all other terms to the right

11m=35

m=35/11

m=3+2/11

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