5(m-3)-4=12-(m+1)

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Solution for 5(m-3)-4=12-(m+1) equation: 



5(m-3)-4=12-(m+1)

We move all terms to the left:

5(m-3)-4-(12-(m+1))=0

We multiply parentheses

5m-(12-(m+1))-15-4=0



We calculate terms in parentheses: -(12-(m+1)), so:

12-(m+1)

determiningTheFunctionDomain
-(m+1)+12

We get rid of parentheses

-m-1+12

We add all the numbers together, and all the variables

-1m+11

Back to the equation:

-(-1m+11)



We add all the numbers together, and all the variables

5m-(-1m+11)-19=0

We get rid of parentheses

5m+1m-11-19=0

We add all the numbers together, and all the variables

6m-30=0

We move all terms containing m to the left, all other terms to the right

6m=30

m=30/6

m=5

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