5(m-8)+2m=2-6(7+8m)

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Solution for 5(m-8)+2m=2-6(7+8m) equation: 



5(m-8)+2m=2-6(7+8m)

We move all terms to the left:

5(m-8)+2m-(2-6(7+8m))=0

We add all the numbers together, and all the variables

5(m-8)+2m-(2-6(8m+7))=0

We add all the numbers together, and all the variables

2m+5(m-8)-(2-6(8m+7))=0

We multiply parentheses

2m+5m-(2-6(8m+7))-40=0



We calculate terms in parentheses: -(2-6(8m+7)), so:

2-6(8m+7)

determiningTheFunctionDomain
-6(8m+7)+2

We multiply parentheses

-48m-42+2

We add all the numbers together, and all the variables

-48m-40

Back to the equation:

-(-48m-40)



We add all the numbers together, and all the variables

7m-(-48m-40)-40=0

We get rid of parentheses

7m+48m+40-40=0

We add all the numbers together, and all the variables

55m=0

m=0/55

m=0

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