5(n+2)=108+2(n+(n+1))

Solution for 5(n+2)=108+2(n+(n+1)) equation:

Simplifying
5(n + 2) = 108 + 2(n + (n + 1))

Reorder the terms:
5(2 + n) = 108 + 2(n + (n + 1))
(2 * 5 + n * 5) = 108 + 2(n + (n + 1))
(10 + 5n) = 108 + 2(n + (n + 1))

Reorder the terms:
10 + 5n = 108 + 2(n + (1 + n))

Remove parenthesis around (1 + n)
10 + 5n = 108 + 2(n + 1 + n)

Reorder the terms:
10 + 5n = 108 + 2(1 + n + n)

Combine like terms: n + n = 2n
10 + 5n = 108 + 2(1 + 2n)
10 + 5n = 108 + (1 * 2 + 2n * 2)
10 + 5n = 108 + (2 + 4n)

Combine like terms: 108 + 2 = 110
10 + 5n = 110 + 4n

Solving
10 + 5n = 110 + 4n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-4n' to each side of the equation.
10 + 5n + -4n = 110 + 4n + -4n

Combine like terms: 5n + -4n = 1n
10 + 1n = 110 + 4n + -4n

Combine like terms: 4n + -4n = 0
10 + 1n = 110 + 0
10 + 1n = 110

Add '-10' to each side of the equation.
10 + -10 + 1n = 110 + -10

Combine like terms: 10 + -10 = 0
0 + 1n = 110 + -10
1n = 110 + -10

Combine like terms: 110 + -10 = 100
1n = 100

Divide each side by '1'.
n = 100

Simplifying
n = 100