5(n+3)+2(n-4)=49

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Solution for 5(n+3)+2(n-4)=49 equation: 



5(n+3)+2(n-4)=49

We move all terms to the left:

5(n+3)+2(n-4)-(49)=0

We multiply parentheses

5n+2n+15-8-49=0

We add all the numbers together, and all the variables

7n-42=0

We move all terms containing n to the left, all other terms to the right

7n=42

n=42/7

n=6

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