5(n+3)+9=3(n-2)+1

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Solution for 5(n+3)+9=3(n-2)+1 equation: 



5(n+3)+9=3(n-2)+1

We move all terms to the left:

5(n+3)+9-(3(n-2)+1)=0

We multiply parentheses

5n-(3(n-2)+1)+15+9=0



We calculate terms in parentheses: -(3(n-2)+1), so:

3(n-2)+1

We multiply parentheses

3n-6+1

We add all the numbers together, and all the variables

3n-5

Back to the equation:

-(3n-5)



We add all the numbers together, and all the variables

5n-(3n-5)+24=0

We get rid of parentheses

5n-3n+5+24=0

We add all the numbers together, and all the variables

2n+29=0

We move all terms containing n to the left, all other terms to the right

2n=-29

n=-29/2

n=-14+1/2

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