5(n+3)-1=4(n-1)+7n

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Solution for 5(n+3)-1=4(n-1)+7n equation: 



5(n+3)-1=4(n-1)+7n

We move all terms to the left:

5(n+3)-1-(4(n-1)+7n)=0

We multiply parentheses

5n-(4(n-1)+7n)+15-1=0



We calculate terms in parentheses: -(4(n-1)+7n), so:

4(n-1)+7n

We add all the numbers together, and all the variables

7n+4(n-1)

We multiply parentheses

7n+4n-4

We add all the numbers together, and all the variables

11n-4

Back to the equation:

-(11n-4)



We add all the numbers together, and all the variables

5n-(11n-4)+14=0

We get rid of parentheses

5n-11n+4+14=0

We add all the numbers together, and all the variables

-6n+18=0

We move all terms containing n to the left, all other terms to the right

-6n=-18

n=-18/-6

n=+3

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