5(n+4)-12=3(n-4)-2n

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Solution for 5(n+4)-12=3(n-4)-2n equation: 



5(n+4)-12=3(n-4)-2n

We move all terms to the left:

5(n+4)-12-(3(n-4)-2n)=0

We multiply parentheses

5n-(3(n-4)-2n)+20-12=0



We calculate terms in parentheses: -(3(n-4)-2n), so:

3(n-4)-2n

We add all the numbers together, and all the variables

-2n+3(n-4)

We multiply parentheses

-2n+3n-12

We add all the numbers together, and all the variables

n-12

Back to the equation:

-(n-12)



We add all the numbers together, and all the variables

5n-(n-12)+8=0

We get rid of parentheses

5n-n+12+8=0

We add all the numbers together, and all the variables

4n+20=0

We move all terms containing n to the left, all other terms to the right

4n=-20

n=-20/4

n=-5

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