5(n-1)(n-1)=0

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Solution for 5(n-1)(n-1)=0 equation: 



5(n-1)(n-1)=0

We multiply parentheses ..

5(+n^2-1n-1n+1)=0

We multiply parentheses

5n^2-5n-5n+5=0

We add all the numbers together, and all the variables

5n^2-10n+5=0

a = 5; b = -10; c = +5;
Δ = b2-4ac
Δ = -102-4·5·5
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{10}{10}=1$

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