5(n-10)+3=7(n-12)+12

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Solution for 5(n-10)+3=7(n-12)+12 equation:



5(n-10)+3=7(n-12)+12
We move all terms to the left:
5(n-10)+3-(7(n-12)+12)=0
We multiply parentheses
5n-(7(n-12)+12)-50+3=0
We calculate terms in parentheses: -(7(n-12)+12), so:
7(n-12)+12
We multiply parentheses
7n-84+12
We add all the numbers together, and all the variables
7n-72
Back to the equation:
-(7n-72)
We add all the numbers together, and all the variables
5n-(7n-72)-47=0
We get rid of parentheses
5n-7n+72-47=0
We add all the numbers together, and all the variables
-2n+25=0
We move all terms containing n to the left, all other terms to the right
-2n=-25
n=-25/-2
n=12+1/2

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