5(n-2)+3(n+6)=3(n-1)+4(n-2)

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Solution for 5(n-2)+3(n+6)=3(n-1)+4(n-2) equation: 



5(n-2)+3(n+6)=3(n-1)+4(n-2)

We move all terms to the left:

5(n-2)+3(n+6)-(3(n-1)+4(n-2))=0

We multiply parentheses

5n+3n-(3(n-1)+4(n-2))-10+18=0



We calculate terms in parentheses: -(3(n-1)+4(n-2)), so:

3(n-1)+4(n-2)

We multiply parentheses

3n+4n-3-8

We add all the numbers together, and all the variables

7n-11

Back to the equation:

-(7n-11)



We add all the numbers together, and all the variables

8n-(7n-11)+8=0

We get rid of parentheses

8n-7n+11+8=0

We add all the numbers together, and all the variables

n+19=0

We move all terms containing n to the left, all other terms to the right

n=-19

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