5(n-2)=-3(2n-4)

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Solution for 5(n-2)=-3(2n-4) equation: 



5(n-2)=-3(2n-4)

We move all terms to the left:

5(n-2)-(-3(2n-4))=0

We multiply parentheses

5n-(-3(2n-4))-10=0



We calculate terms in parentheses: -(-3(2n-4)), so:

-3(2n-4)

We multiply parentheses

-6n+12

Back to the equation:

-(-6n+12)



We get rid of parentheses

5n+6n-12-10=0

We add all the numbers together, and all the variables

11n-22=0

We move all terms containing n to the left, all other terms to the right

11n=22

n=22/11

n=2

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