5(n-3)+4n=78

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Solution for 5(n-3)+4n=78 equation:



5(n-3)+4n=78
We move all terms to the left:
5(n-3)+4n-(78)=0
We add all the numbers together, and all the variables
4n+5(n-3)-78=0
We multiply parentheses
4n+5n-15-78=0
We add all the numbers together, and all the variables
9n-93=0
We move all terms containing n to the left, all other terms to the right
9n=93
n=93/9
n=10+1/3

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