5(n-3)-3n=2(n-7)-1

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Solution for 5(n-3)-3n=2(n-7)-1 equation:


Simplifying
5(n + -3) + -3n = 2(n + -7) + -1

Reorder the terms:
5(-3 + n) + -3n = 2(n + -7) + -1
(-3 * 5 + n * 5) + -3n = 2(n + -7) + -1
(-15 + 5n) + -3n = 2(n + -7) + -1

Combine like terms: 5n + -3n = 2n
-15 + 2n = 2(n + -7) + -1

Reorder the terms:
-15 + 2n = 2(-7 + n) + -1
-15 + 2n = (-7 * 2 + n * 2) + -1
-15 + 2n = (-14 + 2n) + -1

Reorder the terms:
-15 + 2n = -14 + -1 + 2n

Combine like terms: -14 + -1 = -15
-15 + 2n = -15 + 2n

Add '15' to each side of the equation.
-15 + 15 + 2n = -15 + 15 + 2n

Combine like terms: -15 + 15 = 0
0 + 2n = -15 + 15 + 2n
2n = -15 + 15 + 2n

Combine like terms: -15 + 15 = 0
2n = 0 + 2n
2n = 2n

Add '-2n' to each side of the equation.
2n + -2n = 2n + -2n

Combine like terms: 2n + -2n = 0
0 = 2n + -2n

Combine like terms: 2n + -2n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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