5(n-3)=35,n=10

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Solution for 5(n-3)=35,n=10 equation:



5(n-3)=35.n=10
We move all terms to the left:
5(n-3)-(35.n)=0
We add all the numbers together, and all the variables
5(n-3)-(+35.n)=0
We multiply parentheses
5n-(+35.n)-15=0
We get rid of parentheses
5n-35.n-15=0
We add all the numbers together, and all the variables
-30n-15=0
We move all terms containing n to the left, all other terms to the right
-30n=15
n=15/-30
n=-1/2

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