5(n-4)=2(n-1)

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Solution for 5(n-4)=2(n-1) equation: 



5(n-4)=2(n-1)

We move all terms to the left:

5(n-4)-(2(n-1))=0

We multiply parentheses

5n-(2(n-1))-20=0



We calculate terms in parentheses: -(2(n-1)), so:

2(n-1)

We multiply parentheses

2n-2

Back to the equation:

-(2n-2)



We get rid of parentheses

5n-2n+2-20=0

We add all the numbers together, and all the variables

3n-18=0

We move all terms containing n to the left, all other terms to the right

3n=18

n=18/3

n=6

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