5(n-4)=7(2n+1)

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Solution for 5(n-4)=7(2n+1) equation: 



5(n-4)=7(2n+1)

We move all terms to the left:

5(n-4)-(7(2n+1))=0

We multiply parentheses

5n-(7(2n+1))-20=0



We calculate terms in parentheses: -(7(2n+1)), so:

7(2n+1)

We multiply parentheses

14n+7

Back to the equation:

-(14n+7)



We get rid of parentheses

5n-14n-7-20=0

We add all the numbers together, and all the variables

-9n-27=0

We move all terms containing n to the left, all other terms to the right

-9n=27

n=27/-9

n=-3

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