5(n-4)=7(n+3)

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Solution for 5(n-4)=7(n+3) equation: 



5(n-4)=7(n+3)

We move all terms to the left:

5(n-4)-(7(n+3))=0

We multiply parentheses

5n-(7(n+3))-20=0



We calculate terms in parentheses: -(7(n+3)), so:

7(n+3)

We multiply parentheses

7n+21

Back to the equation:

-(7n+21)



We get rid of parentheses

5n-7n-21-20=0

We add all the numbers together, and all the variables

-2n-41=0

We move all terms containing n to the left, all other terms to the right

-2n=41

n=41/-2

n=-20+1/2

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