5(n-6)=4(4n-28)

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Solution for 5(n-6)=4(4n-28) equation: 



5(n-6)=4(4n-28)

We move all terms to the left:

5(n-6)-(4(4n-28))=0

We multiply parentheses

5n-(4(4n-28))-30=0



We calculate terms in parentheses: -(4(4n-28)), so:

4(4n-28)

We multiply parentheses

16n-112

Back to the equation:

-(16n-112)



We get rid of parentheses

5n-16n+112-30=0

We add all the numbers together, and all the variables

-11n+82=0

We move all terms containing n to the left, all other terms to the right

-11n=-82

n=-82/-11

n=7+5/11

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